Slope Line Equation for MATLAB Coding

THIS is a little problem which is mostly faced by Students in MATLAB coding that How to write code for this type of function (Piecewise).

when we write a code for the given code we will convert this one function into three parts.

1. Less then A (-0.5):

Just write the code as 

x = [-1:0.1:1];

for i = 1:1:21

    if (x(i)) < -0.5)

        y(i) = 0

end

end

2. Grater then B (0.5):

and write the code for x > 0.5

x = [-1:0.1:1];

for i = 1:1:21

    if (x(i)) > 0.5)

        y(i) = 1

end

end

3. Between A to B:

and here is little bit complex to find A to B Slop equation.

A point is at (x = -0.5 , y = 0) and B is at (x = 0.5 , y = 1)

then

Line equation format is y = m.x + c 

m is the slope of the line in equation which is = (Delta (y)/ Delta (x)) or (YB - YA) / (XB - XA)

which is in this case 

m = {1 - 0} / {0.5 - (-0.5)}

m = 1

and equation format is (YB - YA) = m (XB - XA) 

here A is start point which we know (-0.5, 0) and finding next point toward B so

YB replace as just Y and XB with X that is unknown point 

Y - 0 = 1 * (X + 0.5)

so the Y = X + 0.5 

if x = -0.5 then y = 0

as shown in above graph

m = 1;

x = [-1:0.1:1];

for i = 1:1:21

    else 

        y(i) = m * x(i) + 0.5;

end

end

for Code and results of MATLAB See HERE

IN THIS CASE: 

A point is at (x = -0.5 , y = -1) and B is at (x = 0.5 , y = 1)

m = {1 - (-1)} / {0.5 - (-0.5)}

m = 2

Y - (-1) = 2 * (X + 0.5)

Y+1 = 2 * X +1

so the Y = 2 * X 

if x = -0.5 then y = -1

as shown in above graph

m = 2;

x = [-1:0.1:1];

for i = 1:1:21

    else 

        y(i) = m * x(i);

end

end

for Code and results of MATLAB See HERE